Area of a Sector

question 1 of 4 Grade: Ten - G10

Q: Find the area of a sector of a circle with radius 14 cm and angle \(45^\circ\).

Did You Know?

For equal roots, the discriminant must be zero: $D = b^2 - 4ac = 0$. Here $a = 1$, $b = 4$, $c = k$, so $4^2 - 4(1)(k) = 0$ ⇒ $16 - 4k = 0$ ⇒ $4k = 16$ ⇒ $k = 4$. Therefore, the statement is correct.

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