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Module Progress: Electrical Resistance

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Electrical Resistance

question 1 of 1 Grade: Twelve - G12

Q: Ohm's law states \(V = I \cdot R\). Is this statement true or false?

Did You Know?

Clear fractions by multiplying first equation by 6: \(3x + 2y = 24\). Multiply second equation by 6: \(2x - 3y = 6\). Now solve: Multiply first by 3: \(9x + 6y = 72\). Multiply second by 2: \(4x - 6y = 12\). Add: \(13x = 84\) ⇒ x = \(\frac{84}{13}\). Substitute into \(3x + 2y = 24\): \(3(\frac{84}{13}) + 2y = 24\) ⇒ \(\frac{252}{13} + 2y = 24\) ⇒ \(2y = 24 - \frac{252}{13} = \frac{312}{13} - \frac{252}{13} = \frac{60}{13}\) ⇒ y = \(\frac{30}{13}\).

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Did You Know?

Clear fractions by multiplying first equation by 6: \(3x + 2y = 24\). Multiply second equation by 6: \(2x - 3y = 6\). Now solve: Multiply first by 3: \(9x + 6y = 72\). Multiply second by 2: \(4x - 6y = 12\). Add: \(13x = 84\) ⇒ x = \(\frac{84}{13}\). Substitute into \(3x + 2y = 24\): \(3(\frac{84}{13}) + 2y = 24\) ⇒ \(\frac{252}{13} + 2y = 24\) ⇒ \(2y = 24 - \frac{252}{13} = \frac{312}{13} - \frac{252}{13} = \frac{60}{13}\) ⇒ y = \(\frac{30}{13}\).

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