First, rewrite the equation as \(x^2 + 6x + 2 = 0\). Using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\) with \(a=1\), \(b=6\), and \(c=2\), we get \(x = \frac{-6 \pm \sqrt{36-8}}{2} = \frac{-6 \pm \sqrt{28}}{2} = \frac{-6 \pm 2\sqrt{7}}{2} = -3 \pm \sqrt{7}\).

Break down complex topics into smaller, manageable chunks for easier recall.

Zambia

• Dickson Tembo – 1 pts

• Mid-point of A Line
• Equation of a Straight Line
• Parallel and Perpendicular Lines
• Area of Rectilinear Figures
• Distance of A Straight Line