To complete the square: 1) Move constant term: $x^2 + 6x = 7$. 2) Take half of coefficient of x $(6/2 = 3)$ and square it $(3^2 = 9)$. 3) Add this to both sides: $x^2 + 6x + 9 = 7 + 9$. 4) Factor left side: $(x + 3)^2 = 16$. 5) Take square root: $x + 3 = \pm4$. 6) Solve: $x = -3 + 4 = 1$ or $x = -3 - 4 = -7$.

Break down complex topics into smaller, manageable chunks for easier recall.

Zambia

• ivwananji siwale – 29 pts

• Distance of A Straight Line
• Mid-point of A Line
• Equation of a Straight Line
• Parallel and Perpendicular Lines
• COMMUNICATION SYSTEMS