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Types of Advertising

question 1 of 1 Grade: Twelve - G12
question 1 of 1 Grade: Twelve - G12

Q: Advertising is effective when sound and vision are used. This effect is best shown by using ...

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Did You Know?

If \(\tan \theta = \frac{3}{4}\), then opposite = 3, adjacent = 4. Hypotenuse = \(\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5\). \(\sec \theta = \frac{\text{hypotenuse}}{\text{adjacent}} = \frac{5}{4}\).

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If \(\tan \theta = \frac{3}{4}\), then opposite = 3, adjacent = 4. Hypotenuse = \(\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5\). \(\sec \theta = \frac{\text{hypotenuse}}{\text{adjacent}} = \frac{5}{4}\).

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