Intestinal Lymphangiectasia
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Did You Know?
Find cos α = √(1 - sin²α) = √(1 - 4/9) = √(5/9) = √5/3. sin β = √(1 - cos²β) = √(1 - 9/16) = √(7/16) = √7/4. tan α = sin α/cos α = (2/3)/(√5/3) = 2/√5. tan β = sin β/cos β = (√7/4)/(3/4) = √7/3. Then tan(α+β) = (tan α + tan β)/(1 - tan α tan β) = (2/√5 + √7/3)/(1 - (2√7)/(3√5)).
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