Tight Junctions
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Did You Know?
z·conjugate(z) = a² + b² = 25. Given a = 7b. Substitute: (7b)² + b² = 25 ⇒ 49b² + b² = 50b² = 25 ⇒ b² = 1/2 ⇒ b = ±1/√2 = ±√2/2. Then a = 7b = ±7√2/2. So z = (7√2/2) + (√2/2)i or z = -(7√2/2) - (√2/2)i.
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