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Area of Rectilinear Figures

question 1 of 3 Grade: Ten - G10
question 1 of 3 Grade: Ten - G10

Q: Find the area of a rectangle with length 12 cm and width 8 cm.

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Quadratic formula: \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\). Here, a=2,b=-3,c=-5. Compute discriminant: (-3)²-4(2)(-5)=9+40=49. So x = [3 ± 7]/4 → x = 2.5 or x = -1.

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Did You Know?

Quadratic formula: \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\). Here, a=2,b=-3,c=-5. Compute discriminant: (-3)²-4(2)(-5)=9+40=49. So x = [3 ± 7]/4 → x = 2.5 or x = -1.

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