Binomial Theorem (G12)
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This is an incomplete quadratic: \(2x^2 - 8 = 0\) ⇒ \(2x^2 = 8\) ⇒ \(x^2 = 4\) ⇒ \(x = \pm\sqrt{4}\) ⇒ \(x = \pm2\). So the solutions are \(x = 2\) and \(x = -2\).
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