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Common Logarithms

question 1 of 2 Grade: Ten - G10
question 1 of 2 Grade: Ten - G10

Q: Evaluate \(\log_{10} 1000\).

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Simple interest formula: A = P(1 + rt), where P=50000, r=0.09, t=3. So A = 50000(1 + 0.09*3) = 50000(1 + 0.27) = 50000 * 1.27 = 63500. So bond is worth K63 500.00.

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Did You Know?

Simple interest formula: A = P(1 + rt), where P=50000, r=0.09, t=3. So A = 50000(1 + 0.09*3) = 50000(1 + 0.27) = 50000 * 1.27 = 63500. So bond is worth K63 500.00.

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