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Geometric Sequence (GP)

question 1 of 16 Grade: Eleven - G11
question 1 of 16 Grade: Eleven - G11

Q: The sum to infinity of a geometric sequence exists when the common ratio is between -1 and 1

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Did You Know?

First, calculate each part: \(3^{2} = 9\), \(3^{-1} = \frac{1}{3}\), and \(2^{0} = 1\). Then, \(\frac{1}{3} \times 1 = \frac{1}{3}\). Finally, add 9 and \(\frac{1}{3}\) to get \(9\frac{1}{3}\) or \(\frac{28}{3}\).

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Did You Know?

First, calculate each part: \(3^{2} = 9\), \(3^{-1} = \frac{1}{3}\), and \(2^{0} = 1\). Then, \(\frac{1}{3} \times 1 = \frac{1}{3}\). Finally, add 9 and \(\frac{1}{3}\) to get \(9\frac{1}{3}\) or \(\frac{28}{3}\).

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