Add the first two equations to eliminate y: (x + 3y - 2z) + (3x - y + z) = 4x + 2y - z = 14. Multiply the second equation by 2: 6x - 2y + 2z = 18. Add to the third equation: (6x - 2y + 2z) + (x - 2y - 3z) = 7x - 4y - z = 11. Solve the resulting two equations with the first, or by substitution/elimination. The solution is x = 2, y = 1, z = 0.

Break down complex topics into smaller, manageable chunks for easier recall.

Zambia

• Naomi Miselo – 31 pts

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