Probability

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Estimation and Approximation

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question 1 of 1 Grade: Twelve - G12

Q: P(green)=2/5, P(red)=1/4, P(black)=1/5. Find P(blue).

The relationship is z = (k*y)/(x^2). Substitute the given values: 6 = (k*27)/((-3)^2) = (27k)/9 = 3k. Solving for k gives k = 6/3 = 2.

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The relationship is z = (k*y)/(x^2). Substitute the given values: 6 = (k*27)/((-3)^2) = (27k)/9 = 3k. Solving for k gives k = 6/3 = 2.

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