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Quadratic Inequalities

question 1 of 3 Grade: Ten - G10
question 1 of 3 Grade: Ten - G10

Q: Solve the inequality: 2x - 5 > 3

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a=2, b=-3, c=-2. Discriminant = \((-3)^2 - 4(2)(-2) = 9 + 16 = 25\). \(x = \frac{3 \pm \sqrt{25}}{4} = \frac{3 \pm 5}{4}\). So \(x = 2\) or \(x = -0.5\).

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Did You Know?

a=2, b=-3, c=-2. Discriminant = \((-3)^2 - 4(2)(-2) = 9 + 16 = 25\). \(x = \frac{3 \pm \sqrt{25}}{4} = \frac{3 \pm 5}{4}\). So \(x = 2\) or \(x = -0.5\).

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