Quadratic Inequalities

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question 1 of 3 Grade: Ten - G10

Q: Solve x² - 4x + 3 > 0.

This is an incomplete quadratic: $2x^2 - 8 = 0$ ⇒ $2x^2 = 8$ ⇒ $x^2 = 4$ ⇒ $x = \pm\sqrt{4}$ ⇒ $x = \pm2$. So the solutions are $x = 2$ and $x = -2$.

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This is an incomplete quadratic: $2x^2 - 8 = 0$ ⇒ $2x^2 = 8$ ⇒ $x^2 = 4$ ⇒ $x = \pm\sqrt{4}$ ⇒ $x = \pm2$. So the solutions are $x = 2$ and $x = -2$.

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