Ratio and Proportion (G8)

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Geometry Basics (G8)

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question 1 of 2 Grade: Eight - G8

Q: A man bought a car valued at K44,700.00. How many dollars did he pay for it, given that the exchange rate on that day was $1 to K14.90?

Annual depreciation = 20% of 40,000 = 8,000. In 3 years: 3 × 8,000 = 24,000 lost. Value after 3 years = 40,000 - 24,000 = K16,000.

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Annual depreciation = 20% of 40,000 = 8,000. In 3 years: 3 × 8,000 = 24,000 lost. Value after 3 years = 40,000 - 24,000 = K16,000.

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