Simple Interest and Profit/Loss (G8)

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Time, Speed, and Distance (G8)

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question 1 of 11 Grade: Eight - G8

Q: A car bought at K40,000 depreciates at 20% per year (straight-line method). What is its value after 3 years?

We have p = 8 + 6/q. Subtract 8 from both sides: p - 8 = 6/q. Then take reciprocal: q = 6 / (p - 8).

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We have p = 8 + 6/q. Subtract 8 from both sides: p - 8 = 6/q. Then take reciprocal: q = 6 / (p - 8).

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