Transport and Communication in Zambia
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\(\sin \theta = 0.6 = \frac{3}{5}\). So opposite = 3, hypotenuse = 5. Adjacent = \(\sqrt{5^2 - 3^2} = \sqrt{25 - 9} = \sqrt{16} = 4\). \(\cos \theta = \frac{4}{5} = 0.8\).
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