Transport
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TRUE. The distance between two parallel lines \(ax + by + c_1 = 0\) and \(ax + by + c_2 = 0\) is given by \(d = \frac{|c_2 - c_1|}{\sqrt{a^2 + b^2}}\). For these lines: \(3x + 4y - 6 = 0\) and \(3x + 4y - 12 = 0\), so \(d = \frac{|-12 - (-6)|}{\sqrt{3^2 + 4^2}} = \frac{6}{5} = 1.2\) units.
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