Heat Transfer and Temperature Regulation
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Divide both sides by cos 2x (assuming cos 2x ≠ 0): √3 tan 2x = 1 => tan 2x = 1/√3. General solution: 2x = π/6 + nπ => x = π/12 + nπ/2. For 0 ≤ x ≤ 2π: n=0: x=π/12; n=1: x=π/12+π/2=7π/12; n=2: x=π/12+π=13π/12; n=3: x=π/12+3π/2=19π/12. Check for cos 2x=0: if cos 2x=0, then sin 2x=±1, LHS=±√3, RHS=0, not equal. So the four solutions are valid.
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