Solitary Rectal Ulcer Syndrome
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Using Remainder Theorem: f(-2) = r for first polynomial: 5(-8) - 3(4) + a(-2) + 7 = r ⇒ -40 - 12 - 2a + 7 = r ⇒ -45 - 2a = r. g(-2) = 2r for second: 4(-8) + a(4) + 7(-2) - 4 = 2r ⇒ -32 + 4a - 14 - 4 = 2r ⇒ -50 + 4a = 2r. Solve system: r = -45 - 2a and -50 + 4a = 2(-45 - 2a) ⇒ -50 + 4a = -90 - 4a ⇒ 8a = -40 ⇒ a = -5, then r = -45 - 2(-5) = -35.
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